Below is the graph of equation y=

|x−1|-2

. Use this graph to find all values of x such that ...

|x−1|-2>0

now try where
|x-1|-2<0 and |x-1|-2=0

|x−1|-2 > 0

Is the region above the x-axis

So,

x < -1 or x > 3

For |x−1|-2 < 0

-1 < x < 3

For |x−1|-2 = 0,

x = -1, 3

answer: add the !

step-by-step explanation: then we will answer

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64