How many quarts of pure antifreeze must be added to 2 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution?

Let x = amount (quarts) of pure antifreeze added

then

x + .10(2) = .40(x+2)

x + .20 = .40x+.80

x = .40x+.60

.60x = .60

x = 1.0 quart

Step-by-step explanation:

Hope this helps!

do i do it on a graph?

step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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