Find the area of the triangle with A = 60°, b = 11 feet, and c= 8 feet. Round to the nearest tenth.

38.1 sq. ft

Step-by-step explanation:

angle A =  60 deg.

length a = unknown

b = 11 feet

c = 8 feet

angle B  must be larger than angle C

try cos A = 8/11 ?  no  since cos A = 0.5  so this is not a 30-60-90 triangle

Area of triangle = (1/2)* base * height

height = ...

imagine...   8 is hypotenuse and then adjacent leg = 8*cos 60

then height = 8 * sin 60 = 8 * (root(3)/2) = 4*root(3)

Area of triangle A =  (1/2)*11 feet *  4*root(3)

A =22*root(3) sq. ft. = 38.105 sq. ft  = 38.1 sq. ft

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