find the median, first quartile, third quartile, and interquartile range of the data.

12, 31, 9, 20, 36, 5, 22
and
63, 68, 58, 77, 50, 49, 63, 73

Part 1) 12, 31, 9, 20, 36, 5, 22

Sort the data:

5, 9, 12, 20, 22, 31, 36

Median: 20

First Quartile: 9

Third Quartile: 31

IQR: 31 - 9 = 22

and

Part 2) 63, 68, 58, 77, 50, 49, 63, 73

Sort the data:

49, 50, 58, 63, 63, 68, 73, 77

Median: (63÷63)/2 = 63

First Quartile: (50+58)/2 = 54

Third Quartile: (68+73)/2 = 70.5

IQR: 70.5 - 54 = 16.5

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length