"A sample of 64 hotels in Atlanta was selected in order to determine whether or not the average room price is significantly different from $110. The average price of the rooms in the sample was $112. The population standard deviation is known to be $16. Use a 0.05 level of significance. Use this information to answer Questions 16 to 19. What should be the appropriate null and alternative hypotheses for the purpose of your analysis?"

The null and alternative hypothesis are:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average room price in Atlanta is significantly different from $110 (P-value=0.317) .

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average room price in Atlanta is significantly different from $110.

Then, the null and alternative hypothesis are:

The significance level is 0.05.

The sample has a size n=64.

The sample mean is M=112.

The standard deviation of the population is known and has a value of σ=16.

We can calculate the standard error as:

Then, we can calculate the z-statistic as:

This test is a two-tailed test, so the P-value for this test is calculated as:

As the P-value (0.317) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average room price in Atlanta is significantly different from $110.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%