A dart is tossed and hits the dart board shown.
The dart is equally likely to land on any point on
the dart board. Find the probability, as a percent
to the nearest tenth, that the dart lands in the
ring surrounding the bullseye.

4.9%

Step-by-step explanation:

To find the probability of the dart hitting the red circle, we need to find the total area of the board and the area of the red circle.

The area of the board is 16 in * 16 in = 256 in2

The area of the red circle is pi * 2^2 = 12.5664 in2

So the probability of the dart landing on the red circle is:

Probability = area_circle / area_board = 12.5664 / 256 = 0.0491 = 4.91%

Rounding to nearest tenth, we have 4.9%

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

the answer is mp

step-by-step explanation: