H(x) = -(x + 11)2 +1 what is the vertex

with (-11, 1) as the vertex

Step-by-step explanation:

The vertex form of a parabola is given by

y = a (x-h) ^2 +k

where (h,k) is the vertex

h(x) = -(x + 11)^2 +1

is written in vertex form

h(x) = -(x  -  -11)^2 +1

  with (-11, 1) as the vertex

never fear papaguy is here

answer