Can anyone help
3c+5=23

c = 6

To solve for c in the equation you see here,

our goal is to get c by itself.

Our first step will be to isolate the term

containing c which in this problem is 3c.

To isolate 3c, we have to get rid of the +5 by

subtracting 5 from both sides of the equation.

On the left, the +5 and -5 cancel out

and we are simply left with 3c.

On the right, 23 - 5 simplifies to 18.

Now we have 3c = 18.

To get c by itself, since it's being multiplied by 3,

we just divide both sides of the equation by 3.

On the left, the 3's cancel and we are left with c.

On the right, 18/3 simplifies to 6.

So our answer is c = 6.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

i belive those are the ones that are under 90 degreese.