A soccer ball is at rest and is then kicked giving it a final velocity of 6.0 m/s. The ball has a mass of
0.28 kg. If the time of contact between the soccer player's foot and the ball is 0.020 s, what was the
average force applied to the ball?

The average force applied to the ball is 84N

Step-by-step explanation:

This problem bothers on the impulse of a force

Given data

Mass of ball m= 0.28kg

Initial speed u= 0m/s

Final speed v= 6m/s

Time of impact t= 0.02s

We know that the impulse of a force

Ft= mv-mu

Hence the force is

F= (mv-mu)/t

F=m(v-u)/t

F= 0.28(6-0)0.02

F= 1.68/0.02

F= 84N

answer: get jesus in your life

step-by-step explanation:

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right