100 pts

Leonardo is solving the equation 4 (x minus one-fifth) = 2 and two-thirds. His work is shown. Where is his error? 4 (x minus one-fifth) = 2 and two-thirds. Step 1, 4 x minus four-fifths = 2 and two-thirds. Step 2, 4 x = StartFraction 8 over 3 EndFraction + four-fifths. Step 3, 4 x StartFraction 40 over 15 EndFraction + StartFraction 16 over 15 EndFraction. Step 4, 4 x = StartFraction 56 over 15 EndFraction times one-fourth. X = StartFraction 14 over 15 EndFraction. step 1 step 2 step 3 step 4

Which ordered pair (c,d) is a solution to the given system of linear equations- c+2d=13 -9c-4d=-15

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. if the true percentage of voters who vote for the proposition is 63%, what is the probability that, in your sample, exactly 5 do not voted for the proposition before 2 voted for the proposition? the probability is