In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. Find the length of IJ to the nearest tenth of a foot.

We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.

First of all, we will draw a right triangle using our given information as shown in the attachment.  

We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.

We know that tangent relates opposite side of right triangle to adjacent side.

Upon rounding to nearest tenth, we will get:

Therefore, the length of the side IJ is approximately 258.8 units.

for any of you who need the translation here it is

step-by-step explanation:

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