ABCD is a parallelogram.
E is the point where the diagonals AC and BD meet. Prove that triangle ABE is congruent to triangle CDE.

Using SAS they are congruent.

Step-by-step explanation:

E is the point where the diagonals AC and BD meet.

Side: AB = CD

Angle: ∠ABE = ∠EDC

Side: BE = DE

Hence by SAS theorem the two triangles are congruent.

Answer and Step-by-step explanation:

Because this is a parallelogram, by definition, the intersection point of the two diagonals bisects them, making AE = CE and BE = DE.

We also know that ∠AEB = ∠CED because they're vertical angles, so by definition, they're congruent.

Thus, we can use the side-angle-side (SAS) congruency theorem to prove that ΔABE ≅ ΔCDE.

26

step-by-step explanation:

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!