The equation of line QR is x + 2y = 2. What is the equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6)?

y = negative one halfx + seventeen halves
y = 2x − 4
y = negative one halfx + seven halves
y = 2x + 16

Any perpendicular line has a negative reciprocal slope. So your slope would be 2. The. You would have the equation : y=2x+b. You would then replace the coordinate (5,6) with x and y on your line to solve for b. Your equation would be : y=2x-4

Step-by-step explanation:

Y=2x-4

because I took the exam

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this