Connor randomly chooses a card from a deck of numbered cards. the cards are numbered 1 through 10, and each number appears only one time. What is the probability that the card Connor chooses has a number on it that is even or divisible by 5?
1) 7/10
2) 3/5
3) 1/2
4) 4/5

Probability that the card Connor chooses has a number on it that is even or divisible by 5 is (3/5) or 0.6.

Step-by-step explanation:

We are given that Connor randomly chooses a card from a deck of numbered cards. the cards are numbered 1 through 10, and each number appears only one time.

And we have to find the probability that the card Connor chooses has a number on it that is even or divisible by 5.

Let the Probability that card Connor chooses has a number on it that is even = P(A)

Probability that card Connor chooses has a number on it that is divisible by 5 = P(B)

Probability that card Connor chooses has a number on it that is even and divisible by 5 =  

Probability that card Connor chooses has a number on it that is even or divisible by 5 =  

Here, Even numbers are = {2, 4, 6, 8, 10} = 5

Numbers divisible by 5 = {5, 10} = 2

Also, Number which is even and also divisible by 5 = {10} = 1

Total numbers = 10

Now, Probability that card Connor chooses has a number on it that is even =    = 0.5

Probability that card Connor chooses has a number on it that is divisible by 5 =    = 0.2

Probability that card Connor chooses has a number on it that is even and divisible by 5 =    = 0.1

Now,    

                             =  0.5 + 0.2 - 0.1

                             =  0.6  =  

Hence, probability that the card Connor chooses has a number on it that is even or divisible by 5 is 0.6.

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2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !