A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to
-10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three
significant figures

Mass of tin sample

is ≈ 95.7g

Explanation:

This problem bothers on heat calorimetry/capacity of a substance.

Given data

Specific heat capacity of tin

Cp = 0.227 J/g•°C

Initial temperature of tin θ1= 15°C

Final temperature of tin θ2= -10°C

Heat released Q= 543 J

Mass of tin m=

We know that quantity of heat is given as

Q=mcΔθ

Substituting our given data and solving for mass m we have

543= m*0.227*(-10-15)

543= m*0.227*(-25)

543= - 5.675m

m=543/-5.675

= -95.68

Mass of tin is ≈ 95.7g

What is Quantity of heat?

Quantity of heat is the amount of heat absorbed or given out by a body Q=mcθ