A rocket is launched from the top of a 30 foot cliff with an initial velocity of 150 feet per second. The height, h, of the rocket after t seconds is given by the equation

h = - 1672 +150t + 30. How long after the rocket is launched will it be 20 feet from the ground?

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

$205,000 here you go i had to guess it but i got it correct so yeah