If the factors of quadratic function g are (x-7) and (x+3), what are the zeros of function g?

Step-by-step explanation:

1. you set each expression equal to 0.

x-7=0 and x+3=0

2. Next you need to get the variable by itself so you would add 7 to both sides on the first equation and subtract 3 from both sides for the second one.

3. So your answers would be x=7 and x=-3. Those are the zeros.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!