Jessica is asked to write a quadratic equation to represent a function that goes through the point (8, –11) and has a vertex at (6, –3). Her work is shown below.

–11 = a(8 – 6)2 – 3
–11 = a(2)2 – 3
–11 = 4a – 3
–8 = 4a
a = –2

After Jessica gets stuck, she asks Sally to help her finish the problem. Sally states that Jessica needs to write the quadratic equation using the value she found for a, –2, and the point (8, –11).

Evaluate Jessica’s work and Sally’s review to determine which statement is true.

the answer is C

Step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105