HELP URGANT WILL GIVE 20 POINTS AND BRAINLIEST FOR FAST AND ACCURATE ANSWER !!!
What is the relationship between the sine and cosine of the complementary angles in this diagram?

Drag and drop the answers into the boxes to correctly complete the statements.

Both cos(17°) and sin(x°) can be represented by the ratio- . The angles measuring 17° and x° are complementary angles. This means x° + 17° =- . Therefore, x = -. Since cos(17°)=sin(x°) , this also shows that cos(17°)=sin(- )°.

these are the possibilities for the blanks:
a/b
a/c
b/c
90 degrees
180 degrees
90-17
180-17

The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement.

A

C

B

Since m∠A = 22º is given, we know m∠B = 68º since there are 180º in the triangle. Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A.

If we write, m∠B = 90º - m∠A    (or m∠A = 90º - m∠B ), and we substitute into the original observation, we have:

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)