A business owner noted the features of the 100 cars parked at the business. Here are the results:
Sunroof
11
12
1820
14
6
25
2 doors
4 doors
Given that a randomly selected car has a sunroof, find the probability the car has 4 doors.
P (4 doors | sunroof) =

The probability of a selected car being a 4 door car, given that the car has a sunroof = 0.40

Step-by-step explanation:

The complete question is presented in the attached image.

The conditional probability, of event A happening, given that event B has happened, P(A|B), is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

So, the required probability of a selected car being a 4 door car, given that the car has a sunroof is given as

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

Note that the probability of an event is given as the number of elements in that event divided by the Total number of events.

P (4 doors n sunroof)

= n (4 doors n sunroof) ÷ n (total)

From the Venn Diagram in the attached image,

n (4 doors n sunroof) = 20 + 0 = 20

n (total) = 100

P (4 doors n sunroof) = (20/100) = 0.20

P(sunroof) = n(sunroof) ÷ n(total)

n(sunroof) = 12 + 18 + 20 + 0 = 50

n(total) = 100

P(sunroof) = (50/100) = 0.50

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

= (0.20/0.50) = 0.40

Hope this Helps!!!

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/