DAVID G. BARSHELL. SR. SCHOOL SYSTEM
(DAGBASS):
Royal Kids Preparatory (ROPKIP)
Daycare, Elem. Jr. & Sr. High School
Barclay Mission Road, Paynesville, Liberia
Subject: Mathematics
Class: 11th Grade (4th Marking Period Test)
Name:
Date:
Score
Part I: Objectives (4 points each)
Direction: Circle the correct letter that bears the correct answers(NO ERANUS
1. Give 0º =0–90°, solve the value of 0 in cos 0= sin e
a, 30°
b. 60°
c. 45°
d. 90°
2. Solve for x in cos? x +2 = 3
a. 45°
b. 0°
c. 90°
d. 60°
3. In the interval 0º < y < 360°, determine the values of y in 3cos y - 2 = 0
i. 48.2
ii, 228.2°
iii. 311.8°

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.