In trapezoid $WXYZ$, $\overline{XY} \parallel \overline{WZ}$, $\angle WXZ = 105^\circ$, $\angle W = 43^\circ$, and $\angle Y = 141^\circ$. Find $\angle YXZ$, in degrees.

32 degrees

Step-by-step explanation:

The diagram of the problem is drawn and attached.

In Triangle WXZ

105+43+=180 (Sum of Angles in a Triangle)

148+=180

=180-148

=32 degrees

Since |XY|//|WZ| (parallel to)

= (Alternate Angles)

Therefore:

=32 degrees

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