Alfonso graphs the inequality x greater-than negative 8 using the steps below.

Step 1: Draw a number line, and place an open circle at –8.
A number line going from negative 13 to negative 3. An open circle is at negative 8.
Step 2: Shade to the left of –8 to represent the infinite solutions to x greater-than negative 8.
A number line going from negative 13 to negative 3. An open circle is at negative 8. Everything to the left of the circle is shaded.
Step 3: Check work by substitution.
x = negative 9
Negative 9 greater-than negative 8 False

Which best describes the situation?
i know its kinda hard
A-The graph is incorrect. He should have used a closed circle at –8.
B-The graph is incorrect. He should have shaded to the right of –8.
C-The graph is correct. He should have checked his work with a number that was not on the shaded portion of the graph.
D-The graph is correct. He should have checked his work using –8.

B-The graph is incorrect. He should have shaded to the right of –8.

Step-by-step explanation:

We examine the steps Alfonso follows in graphing the inequality x > -8.

Step 1: Draw a number line, and place an open circle at –8.

A number line going from negative 13 to negative 3. An open circle is at negative 8.

The first step is correct, since we use an open circle for > or < and a closed circle for .

Step 2: Shade to the left of –8 to represent the infinite solutions to x greater-than negative 8.

This step is incorrect since values to the left are always less than.

He should have shaded to the right of -8.

The error made is Option B.

CHECK:

x=-7

-7>-8 (TRUE)

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )