Steve had two spinners in front of him. The first one was numbered 1-6, and the second was numbered 1-3. If
Steve spins each spinner once, what is the probability that the first spinner will show an odd number and the
second spinner will show a "1"? Fill in the calculation below in fraction form
Plodd then 1) =

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

50-60=10

step-by-step explanation:

answer: b.36 feet

step-by-step explanation: