A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
![P(\frac{B}{M} ) = 0.3030](/tpl/images/0653/4402/28af2.png)
Step-by-step explanation:
Explanation:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
Let 'B' be the event of brown eyes
Total number of males n(M) = 33
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
The probability that a randomly selected student from the class has brown eyes , given they are male
![P(\frac{B}{M} ) = \frac{n(B)}{n(M)}](/tpl/images/0653/4402/d719f.png)
From table the brown eyes from males = 10
![P(\frac{B}{M} ) = \frac{10}{33}](/tpl/images/0653/4402/bc1a1.png)
![P(\frac{B}{M} ) = 0.3030](/tpl/images/0653/4402/28af2.png)
Final answer:-
The probability that a randomly selected student from the class has brown eyes , given they are male
![P(\frac{B}{M} ) = 0.3030](/tpl/images/0653/4402/28af2.png)