Peter rolls a fair dice 114 times. How many times would Peter expect to roll a number greater than 1?

A dice of six faces has 5 numbers bigger than 1 (from 2 to 6).

Then, the number Peter is expecting is : 114 x (5/6) = 95 (times)

Hope this helps!

:)

d

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)