The height (in feet) of a rocket from ground level is given by the function f(t) = -16t2 + 220t. What is the instantaneous velocity of the rocket 12 seconds after its launch?

-164 ft/second.

Step-by-step explanation:

The instantaneous velocity is given by the derivative;

f(t) = -16t^2 + 220t

V = f'(t) = -32t + 220

So at 12 seconds:

V = -32*12 + 220

= -164 ft/second ( It is negative because it is descending).

need more information

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)