Length of rectangle is three times bigger than the width. Area of rectangle is 27. A) find width of rectangle B) find length of rectangle C) find perimeter of rectangle.

What is the answer? I need help to solve it.

Step-by-step explanation:

Let the dimensions of the rectangle be length = L and width = W. Then P = perimeter = 2L + 2W.  A = area of rectangle = L * W.  Finally, L = 3W.

Here A = 27 units^2 = W*(3W) = (3*W^2), or 3W^2 = 27 units^2, or

W^2 = 9 units^2, or W = 3 units.  Then L = 3W = 3(3 units) = 9 units.

The length of the rectangle is 9 units.  See above.

The perimeter of the rectangle is 2(9 units) + 2(3 units) = 24 units.

3

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)