John is painting a picture. He has green, red, yellow, purple, orange and blue paint. He wants to use four different colors on this picture. If order does not matter, how many ways can John pick four colors for his picture, if one of them is green?

I'm gonna say maybe 10 yah 10

here's why

In can pick in 10 ways.

Solution:

John has green, red, yellow, purple, orange, and blue paint = total 6 colours

he wants to have 4 different colours in the painting.

But in those 4 colors green is must, it should always be there.

So except green we have total 5 colours (red, yellow, purple, orange, and blue) from which we can pick any 3 colors(as green will be one in four colours).

Then we can choose 3 colours from 5 colours in x ways.  

x ways = = \left(\frac{5 !}{3 !(5-3) !}\right)=(3!(5−3)!5!)

=\left(\frac{5 !}{3 ! \times 2 !}\right)=(3!×2!5!)

=\frac{5 \times 4 \times 3 !}{3 ! \times 2 !}=3!×2!5×4×3!

=\frac{5 \times 4}{2}=25×4

=\frac{20}{2} = 10=220=10

Step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

a triangular prism is a 3 dimensional shape composed of triangles and rectangles. it is made from two triangular bases and three rectangular sides.