M∠ABDm, angle, A, B, D is a straight angle.
\qquad m \angle CBD = 8x + 16^\circm∠CBD=8x+16
∘
m, angle, C, B, D, equals, 8, x, plus, 16, degrees
\qquad m \angle ABC = 6x - 60^\circm∠ABC=6x−60
∘
m, angle, A, B, C, equals, 6, x, minus, 60, degrees
Find m\angle ABCm∠ABCm, angle, A, B, C:

i dont understand the question? ?

step-by-step explanation:

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

c(x)= 6x + 3

step-by-step explanation: