Please solve anyone you can

See below.

Step-by-step explanation:

I can't do all these for you but I'll show you how they are done by taking some samples.

k) 2^x = 32

Take logs of both sides

log 2^x = log 32

x log 2 = log 32

x = log 32 / log 2   Using your calculator to find the log values:

x = 5.

r) 9^(x + 1) = 81

log 9^(x + 1) = log 81

x + 1 log 9 = log 81

x + 1 = log81 / log9 = 2

x + 1 = 2

x = 1.

The above method is a general way to do these using logs but with some of the simpler ones you don't have to use logs at all:

For example :

3^x = 27

We know that 3^3 is 27 so

3^x = 3^3  and so:

x = 3.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

homozygous. one is homozygous, while two is heterozygous.