Describe the domain and range of y=2(3)^x-2+5

the domain is "the set of all real numbers."

the range of the given function is (5, infinity)

Step-by-step explanation:

This is an exponential function.  For the sake of clarity you must enclose "x - 2" inside parentheses:  f(x) = 2(3)^(x-2).  This function is defined for all real x-values, so the domain is "the set of all real numbers."  

Focusing on  (3)^x:  This has the same shape as the basic exponential y = e^x; the graph starts in Quadrant II and increases with x, more and more rapidly as you pass x = 0.  The functions y = e^x and that of y = 3^x are always positive.  Likewise in the case of f(x) = 2(3)^(x-2):  the function is always positive.  If we look at f(x) = 2(3)^(x-2) alone, we conclude that the domain is (0, infinity).  But that " + 5 " in y=2(3)^(x-2) + 5 translates the entire graph of f(x) = 2(3)^(x-2) upward by 5 units.

Thus, the range of the given function is (5, infinity).

it should be a and d. lmk if i'm wrong xd