Robert wants to buy lights around the edge of his deck the deck is 49feet and 26feet wide how many yards of lights does he need

50 yards

Step-by-step explanation:

Let l = length, w = width, and P = perimeter in feet. Let x equal perimeter in yards.

To solve this problem, we first need to find the perimeter of the deck.

To do so, use the formula 2l + 2w = P.

Since the deck is 49 feet long and 26 feet wide, plug in 49 for l and 26 for w.

2(49) + 2(26) = P

Evaluating 2*49 and 2*26, the equation becomes 98 + 52 = P.

Evaluating 98 + 52, the equation becomes 150 = P.

The next step in this problem is to convert feet to yards. We know that Robert needs 150 feet of lights. Since there are three feet in a yard, we can use the formula P = 3x to find the amount of yards of lights Robert needs.

Plugging in 150 for P, the equation becomes 150 = 3x.

Dividing both sides by 3, the equation becomes 50 = x.

Therefore, the final answer is 50 yards.

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80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !