At which root does the graph of f(x) = (x+4)6(x + 7)5 cross the x axis?

x = -7

Step-by-step explanation:

Our function is . Notice that our possible roots are when x + 4 = 0 and when x + 7 = 0. So, our roots are -4 and -7.

However, the power above x + 4 is even, meaning the graph will simply touch the x-axis at x = -4, but not pass through. The power above x + 7, though, is odd, which means the graph will cross the x-axis.

Thus, the answer is x = -7.

x = -7

Step-by-step explanation:

f(x) = (x+4)⁶(x + 7)⁵

The roots are when f(x) = 0

(x+4)⁶ = 0

x = -4 (multiplicity 6)

(x+7)⁵ = 0

x = -7 (multiplicity 5)

The graph is tangential to the x-axis on roots with even multiplicity, crosses tge x-axis at roots with odd multiplicity

This graph cuts/crosses the x-axis at x = -7

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation:

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: