What is the formula for a line that passes through point (6,5) and runs perpindicular to a line with a slope of 1/2

Using THIS formula:

(y-y₁) = m(x-x₁)

PLUGGING IT IN:

(y-5) = 1/2(x-6)

Is this what your teacher is looking for?

the answer is c. 23/3

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10