Jakob was asked to write an equation and solve this problem. Max saved enough money to buy three tickets to a baseball game. If each ticket costs $18.75, how much money did Max save? Jakob’s work is shown below.

$56.25

Step-by-step explanation:

We know that Max has just enough money to buy 3 tickets that each cost $18.75, so let's write the expression:

18.75 * 3

We just solve this by multiplication:

18.75 * 3 = $56.25

Max saved $56.25.

$56.25

Step-by-step explanation:

His savings were equal to the cost of 3 tickets, therefore

Savings = 3 × 18.75

Savings = 56.25

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.