What are the zeros of the polynomial function F(x) = x3 - 5x2 - 6x?

The zeros are {2, 3}

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  

F(x) = x^3 - 5x^2 - 6x

Factoring out x, we get:

F(x) = x(x^2 - 5x - 6)

Factoing the quadratic, we get:

F(x) = x(x - 3)(x - 2) = 0

The zeros are {2, 3}

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet