The length, l, of a rectangle is 3 inches greater than its width, w. The perimeter of the rectangle is at least 30 inches. Which inequalityshows the range of possible lengths of the rectangle?

l >= 9 and w >= 6

Step-by-step explanation:

The perimeter of the rectangle can be found by:

→ Perimeter = (2 x length) + (2 x width) (1)

Since the length is 3 inches greater than the width:

→ l = w + 3

Also, the perimeter is at least 30 inches

If you substitute the values in the equation 1:

→ (2 x l) + (2 x w) >= 30

→ (2 x (w + 3)) + (2 x w) >= 30

→ 2 x w + 6 + (2 x w) >= 30

→ 4 x w >= 24

→ w >= 6

Since l = w + 3, l >= 9

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)