What are the factors of m^2-12+20

(m-10)(m-2)

Step-by-step explanation:

(I'm assuming you meant m^2-12m+20)

To find the factors of this quadratic equation, we need to find the two numbers which add together to equal -12 and multiply together to equal 20. So, let's do this:

20 = (1*20), (2*10), (4*5)

Now you may be wondering, "but there's no two numbers that add up to -12." You would be right, but there's still more factors!

20 = (-1*-20), (-2*-10), (-4*-5)

The two numbers that add up to -12 and multiply together to equal 20 are -2 and -10. We found the two numbers, so we just need to four term the equation:

(m^2-2m)+(-10m+20)

m(m-2)+-10(m-2)

(m-10)(m-2)

There's our answer.

o= 4(i) +3

step-by-step explanation:

o is your output value and i is your input value. so, for example, if we stuck 7 in as our input, we would first multiply by 4 ( pemdas ), which equals 28. then we would add 3 to 28, for a total output of 31. this may not be a graph, but, it is a way to solve your formula..

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco