Suppose the point (3,1) satisfies the function f(×). what point would satisfy g(x)=-2f(x/2)+1?

(6, -1)

Step-by-step explanation:

Given that point (3,1) satisfies the function f(×).  From the equation

g(x)=-2f(x/2)+1

x/2 = 3

x = 6

Substitute the 1 for f(x/2)

g(x) = -2(1)+1

g(x) = -2 + 1 = -1

The point that would satisfy g(x)=-2f(x/2)+1 is (6, -1)

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are

answer: (-6,3)

step-by-step explanation: