For a project, Mr. Green's physics students made rockets. During class last week, the students launched their rockets from the bleachers of the school's outdoor football stadium. The bleacher location where Martin launched his rocket was 48 feet off the ground. The height of Martin's rocket in feet, t seconds after launch, is shown by the function below. h(t) = -16t+88t+48

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

answer: you need the equation in the question so i can answer it

step-by-step explanation:

this is a good question! i'll do some research and come back when i have the answer!