( and 50 points! )

Robert has a collection of nickles, dimes, and quarters. The total value of the coins is $8.50. He has 3 times as many nickles as dimes, and 10 more quarters than dimes. How many of each coin does he have.

As we know:

A nickle is worth 5 cents.

A dime is worth 10 cents.

A quarter is worth 25 cents.

Here is what Robert had:

Number of nickles (a)

Number of dimes (b)

Number of quarters (c)

Here is assumption:

5a + 10b + 25c = 850

a = 3b

c = b + 10

=> 5(3b) + 10b + 25(b + 10) = 850

=> 50b + 250 = 850

=> 50b = 600

=> b = 600/50 = 12

=> a = 3b = 3 x 12 = 36

=> c = b + 10 = 12 + 10 = 22

=> Number of nickles: 36

=> Number of dimes: 12

=> Number of quarters: 22

Hope this helps!

:)

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6