Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

We divided the figure into 1 triangle and 3 rectangles (as shown in attached pic).

Adding up the area of them, we get the total area:

A = area of triangle + area of 3 rectangles

   =  base x height/2 + length1 x width1 + length2 x width2 + length3 x width3

   = 6 x (2 + 11 + 5 - 4 -3)/2 + 2 x 2 + 11  x (5 + 2) + 5 x 9

   = 159 (m2)

Hope this helps!

:)

Step 1) Split the figure into separate shapes

Triangle: 6 x 11

Small square: 2 x 2

Large rectangle (center): 16 x 7

Medium rectangle (bottom): 2 x 5

Step 2) Find the area of each shape

Triangle: A = 6 x 11 x 1/2 = 33

Small square: A = 2 x 2 = 4

Large rectangle (center): A = 16 x 7 = 112

Medium rectangle (bottom): A = 2 x 5 = 10

Step 3) Add the areas together

A = 33 + 4 + 112 + 10 = 159 square meters

Hope this helps! :)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3