A state park has a normally distributed daytime temperatures in the month of June. The mean temperature is 75 Fahrenheit and then standard deviation of 7. What is the probability the temperature is above 82F?

0.16

Step-by-step explanation:

This probability is the area under the standard normal curve to the right of 82.  Note that 82 is ONE standard deviation above the mean:  75 + 7 = 82.

According to the Empirical Rule, 68% of data lies within one standard deviation of the mean.  In other words, 34% lies between the mean and one standard deviation above the mean.  The remaining area under the standard normal curve is thus (100% - 68%), or 32%.  Half of that is 16%.  

The probability that the temperature is above 82, or above 1 standard deviation above the mean, is 16%, which we can also express as 0.16.

Alternatively, use a calculator with built-in statistical functions.  In this case the desired result is found by executing the following command:

normcdf(82, 10000, 75, 7).  The desired result is 0.1587, or approximately 0.16.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer