PLZ HELP! I am stuck on his question.
The ages of two exercise groups at a local fitness center are listed below.
Group A: 37 36 32 41 42 36 44 45
Group B: 26 40 38 36 42 40 40 36
Which statement about the data is true?
The mean age is the same for both groups
The range of ages is greater in Group A than in Group B
The mode of the ages for both groups is 36
The median age is the same for both groups

The median age is the same for both groups

Step-by-step explanation:

Group A:

37, 36, 32, 41, 42, 36, 44, 45

32, 36, 36, 37, 41, 42, 44, 45

Mean: (32+36+36+37+41+42+44+45)÷8=39.125

Range: 45-32=13

Mode: 36

Median: (41+37)÷2=39

Group B:

26, 40, 38, 36, 42, 40, 40, 36

26, 36, 36, 38, 40, 40, 40, 42

Mean:  (26+36+36+38+40+40+40+42)÷8=37.25

Range: 42-26=16

Mode: 40

Median: (40+38)÷2=39

Only the median in both groups are the same.

3rd choice:

Mode for A = 36. Mode for B = 36.

Step-by-step explanation:

Group A: 37 36 32 41 42 36 44 45

Mean age = 313 / 8 = 39.1

Group B: 26 40 38 36 42 40 40 36

Mean age = 298 / 8 = 37.3.

Range for Group A = 45 - 32 = 13

Range for Group B = 42 - 26 = 16.

Both  A and B have 2 instances of age 36.

Mode for A = 36. Mode for B = 36.

i need the options

step-by-step explanation:

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: