Z1=3cispi and z2=5cis(pi/2)

If z1*z2=a+bi, then a=, b=

Step-by-step explanation:

Given two complex number Z1=3cispi and z2=5cis(pi/2)

In polar form;

z1 =

z1 = 3(-1+i0)

z1 = -3+0i

Z2 =

Z2 = 5(0+i)

Z2 = 0+5i

Z1*Z2 =  (-3+0i)(0+5i)

Z1*Z2 = 0 - 15i +0i + 0i²

Z1*Z2 = 0-15i

comparing 0-15i with a + bi;

a = 0 and b = -15

560

step-by-step explanation:

giggidy

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step-by-step explanation: