What is the mean absolute deviation of Astrid's data? To answer the question, first find the mean Next, fill in the table for the absolute deviation
of each score in the data set from the mean. Then find the sum of the deviations. Finally, use the sum of the absolute deviations to find the mean
absolute deviation
B IV x x Font Sizes
E *
Absolute Deviation from Mean Score
Astrid's Scores
mean - Individual score
15
20
25
15
0
55
20
35
15
30
10
5
um delations

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.

i honestly dont know