A shipping container has a volume of 2,880 cubic inches. Which could be the dimensions of the container?

Missing part of the question

- 10 in, by 12 in. by 24 in.

- 12 in. by 15 in. by 18-in.

- 10 in. by 16 in. by 20 in.

- 12 in. by 12 in. by 20 in.

The possible dimensions of the container are

- 10 in, by 12 in. by 24 in

- 12 in. by 12 in. by 20 in

Step-by-step explanation:

Given

Volume of the container = 2,880 cubic inches

Required

Possible dimensions of the container

To solve this question, the following assumption has to be made;

It'll be assumed that the container is a rectangular

To calculate the volume of a rectangular figure, we simply multiply the dimensions of the figure,

This implies that; we'll test each of the given options.

Which ever gives 2,880 is the right answer.

- 10 in, by 12 in. by 24 in.

cubic inches

- 12 in. by 15 in. by 18-in.

cubic inches

- 10 in. by 16 in. by 20 in.

cubic inches

- 12 in. by 12 in. by 20 in.

cubic inches

From the calculation above, only option A and D gives 2,880;

Hence, the possible dimensions of the container are

- 10 in, by 12 in. by 24 in

- 12 in. by 12 in. by 20 in

translate k to n and reflect across the line containing jk.

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40