What is the equation of the line that passes through the point (-6,-6)(−6,−6) and has a slope of 2/3?

y = 2/3 x -2

Step-by-step explanation:

We have a point and a slope

y = mx+b

The slope, m, = 2/3

y = 2/3 x+ b

The point is (-6,-6)

Substitute this into the equation to solve for b

-6 = 2/3 (-6) +b

-6 = -4+b

Add 4 to each side

-6+4 = -4+4+b

-2 =b

Substitute into the equation

y = 2/3 x+ b

y = 2/3 x -2

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

i have no idea just need points sorry

step-by-step explanation: