What is the constant rate of change in the function y=5x? *

a.1/5
b. x
c.5
d.1

This is the same as the slope because this is a linear equation

y = 5x is the same as y = 5x+0 which compares to y = mx+b

m = 5 is the slope = rate of change

b = 0 is the y intercept = starting amount

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°